14(t-3)-2(t+2)=10(3t-4)

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Solution for 14(t-3)-2(t+2)=10(3t-4) equation: 



14(t-3)-2(t+2)=10(3t-4)

We move all terms to the left:

14(t-3)-2(t+2)-(10(3t-4))=0

We multiply parentheses

14t-2t-(10(3t-4))-42-4=0



We calculate terms in parentheses: -(10(3t-4)), so:

10(3t-4)

We multiply parentheses

30t-40

Back to the equation:

-(30t-40)



We add all the numbers together, and all the variables

12t-(30t-40)-46=0

We get rid of parentheses

12t-30t+40-46=0

We add all the numbers together, and all the variables

-18t-6=0

We move all terms containing t to the left, all other terms to the right

-18t=6

t=6/-18

t=-1/3

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