14(d+7)=3(d-5)+11d

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Solution for 14(d+7)=3(d-5)+11d equation: 



14(d+7)=3(d-5)+11d

We move all terms to the left:

14(d+7)-(3(d-5)+11d)=0

We multiply parentheses

14d-(3(d-5)+11d)+98=0



We calculate terms in parentheses: -(3(d-5)+11d), so:

3(d-5)+11d

We add all the numbers together, and all the variables

11d+3(d-5)

We multiply parentheses

11d+3d-15

We add all the numbers together, and all the variables

14d-15

Back to the equation:

-(14d-15)



We get rid of parentheses

14d-14d+15+98=0

We add all the numbers together, and all the variables

113!=0

There is no solution for this equation

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