14(40-8x)=19x+2-5x

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Solution for 14(40-8x)=19x+2-5x equation: 



14(40-8x)=19x+2-5x

We move all terms to the left:

14(40-8x)-(19x+2-5x)=0

We add all the numbers together, and all the variables

14(-8x+40)-(14x+2)=0

We multiply parentheses

-112x-(14x+2)+560=0

We get rid of parentheses

-112x-14x-2+560=0

We add all the numbers together, and all the variables

-126x+558=0

We move all terms containing x to the left, all other terms to the right

-126x=-558

x=-558/-126

x=4+3/7

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