13z-8(z+1)=2(z-3)+3z

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Solution for 13z-8(z+1)=2(z-3)+3z equation:


Simplifying
13z + -8(z + 1) = 2(z + -3) + 3z

Reorder the terms:
13z + -8(1 + z) = 2(z + -3) + 3z
13z + (1 * -8 + z * -8) = 2(z + -3) + 3z
13z + (-8 + -8z) = 2(z + -3) + 3z

Reorder the terms:
-8 + 13z + -8z = 2(z + -3) + 3z

Combine like terms: 13z + -8z = 5z
-8 + 5z = 2(z + -3) + 3z

Reorder the terms:
-8 + 5z = 2(-3 + z) + 3z
-8 + 5z = (-3 * 2 + z * 2) + 3z
-8 + 5z = (-6 + 2z) + 3z

Combine like terms: 2z + 3z = 5z
-8 + 5z = -6 + 5z

Add '-5z' to each side of the equation.
-8 + 5z + -5z = -6 + 5z + -5z

Combine like terms: 5z + -5z = 0
-8 + 0 = -6 + 5z + -5z
-8 = -6 + 5z + -5z

Combine like terms: 5z + -5z = 0
-8 = -6 + 0
-8 = -6

Solving
-8 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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