13y-(5-2y)=5(3y-1)

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Solution for 13y-(5-2y)=5(3y-1) equation:


Simplifying
13y + -1(5 + -2y) = 5(3y + -1)
13y + (5 * -1 + -2y * -1) = 5(3y + -1)
13y + (-5 + 2y) = 5(3y + -1)

Reorder the terms:
-5 + 13y + 2y = 5(3y + -1)

Combine like terms: 13y + 2y = 15y
-5 + 15y = 5(3y + -1)

Reorder the terms:
-5 + 15y = 5(-1 + 3y)
-5 + 15y = (-1 * 5 + 3y * 5)
-5 + 15y = (-5 + 15y)

Add '5' to each side of the equation.
-5 + 5 + 15y = -5 + 5 + 15y

Combine like terms: -5 + 5 = 0
0 + 15y = -5 + 5 + 15y
15y = -5 + 5 + 15y

Combine like terms: -5 + 5 = 0
15y = 0 + 15y
15y = 15y

Add '-15y' to each side of the equation.
15y + -15y = 15y + -15y

Combine like terms: 15y + -15y = 0
0 = 15y + -15y

Combine like terms: 15y + -15y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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