13y-(11(9-y)-18)=5y+3(7-5y)

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Solution for 13y-(11(9-y)-18)=5y+3(7-5y) equation: 



13y-(11(9-y)-18)=5y+3(7-5y)

We move all terms to the left:

13y-(11(9-y)-18)-(5y+3(7-5y))=0

We add all the numbers together, and all the variables

13y-(11(-1y+9)-18)-(5y+3(-5y+7))=0



We calculate terms in parentheses: -(11(-1y+9)-18), so:

11(-1y+9)-18

We multiply parentheses

-11y+99-18

We add all the numbers together, and all the variables

-11y+81

Back to the equation:

-(-11y+81)





We calculate terms in parentheses: -(5y+3(-5y+7)), so:

5y+3(-5y+7)

We multiply parentheses

5y-15y+21

We add all the numbers together, and all the variables

-10y+21

Back to the equation:

-(-10y+21)



We get rid of parentheses

13y+11y+10y-81-21=0

We add all the numbers together, and all the variables

34y-102=0

We move all terms containing y to the left, all other terms to the right

34y=102

y=102/34

y=3

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