13y+22=12(y+2)

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Solution for 13y+22=12(y+2) equation: 



13y+22=12(y+2)

We move all terms to the left:

13y+22-(12(y+2))=0



We calculate terms in parentheses: -(12(y+2)), so:

12(y+2)

We multiply parentheses

12y+24

Back to the equation:

-(12y+24)



We get rid of parentheses

13y-12y-24+22=0

We add all the numbers together, and all the variables

y-2=0

We move all terms containing y to the left, all other terms to the right

y=2

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