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13x=x2+30
We move all terms to the left:
13x-(x2+30)=0
We add all the numbers together, and all the variables
-(+x^2+30)+13x=0
We get rid of parentheses
-x^2+13x-30=0
We add all the numbers together, and all the variables
-1x^2+13x-30=0
a = -1; b = 13; c = -30;
Δ = b2-4ac
Δ = 132-4·(-1)·(-30)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*-1}=\frac{-20}{-2} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*-1}=\frac{-6}{-2} =+3 $
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