13x=3x2+4

Solution for 13x=3x2+4 equation:

13x=3x^2+4

We move all terms to the left:

13x-(3x^2+4)=0

We get rid of parentheses

-3x^2+13x-4=0

a = -3; b = 13; c = -4;
Δ = b2-4ac
Δ = 132-4·(-3)·(-4)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-11}{2*-3}=\frac{-24}{-6}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+11}{2*-3}=\frac{-2}{-6}
=1/3
$