13x=(4-x)2-3x-(4-x)2

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Solution for 13x=(4-x)2-3x-(4-x)2 equation: 



13x=(4-x)2-3x-(4-x)2

We move all terms to the left:

13x-((4-x)2-3x-(4-x)2)=0

We add all the numbers together, and all the variables

13x-((-1x+4)2-3x-(-1x+4)2)=0



We calculate terms in parentheses: -((-1x+4)2-3x-(-1x+4)2), so:

(-1x+4)2-3x-(-1x+4)2

We add all the numbers together, and all the variables

-3x+(-1x+4)2-(-1x+4)2

We multiply parentheses

-3x-2x+2x+8-8

We add all the numbers together, and all the variables

-3x

Back to the equation:

-(-3x)



We get rid of parentheses

13x+3x=0

We add all the numbers together, and all the variables

16x=0

x=0/16

x=0

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