13x2-9x-34=0

Solution for 13x2-9x-34=0 equation:

13x^2-9x-34=0

a = 13; b = -9; c = -34;
Δ = b2-4ac
Δ = -92-4·13·(-34)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-43}{2*13}=\frac{-34}{26}
=-1+4/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+43}{2*13}=\frac{52}{26}
=2
$