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13x-2/2x+1=4
We move all terms to the left:
13x-2/2x+1-(4)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
13x-2/2x-3=0
We multiply all the terms by the denominator
13x*2x-3*2x-2=0
Wy multiply elements
26x^2-6x-2=0
a = 26; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·26·(-2)
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{61}}{2*26}=\frac{6-2\sqrt{61}}{52} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{61}}{2*26}=\frac{6+2\sqrt{61}}{52} $
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