13w(28w+25)=0

Solution for 13w(28w+25)=0 equation:

13w(28w+25)=0

We multiply parentheses

364w^2+325w=0

a = 364; b = 325; c = 0;
Δ = b2-4ac
Δ = 3252-4·364·0
Δ = 105625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{105625}=325$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(325)-325}{2*364}=\frac{-650}{728}
=-25/28
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(325)+325}{2*364}=\frac{0}{728}
=0
$