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13=5/2(5x-4)
We move all terms to the left:
13-(5/2(5x-4))=0
Domain of the equation: 2(5x-4))!=0We multiply all the terms by the denominator
x∈R
-(5+13*2(5x-4))=0
We calculate terms in parentheses: -(5+13*2(5x-4)), so:We add all the numbers together, and all the variables
5+13*2(5x-4)
determiningTheFunctionDomain 13*2(5x-4)+5
Wy multiply elements
26x(5+5
Back to the equation:
-(26x(5+5)
-(26x10=0
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