13=2/3(-9)+k

Solution for 13=2/3(-9)+k equation:

13=2/3(-9)+k

We move all terms to the left:

13-(2/3(-9)+k)=0


Domain of the equation: 3(-9)+k)!=0

k∈R


We multiply all the terms by the denominator


-(2+13*3(-9)+k)=0


We calculate terms in parentheses: -(2+13*3(-9)+k), so:

2+13*3(-9)+k

determiningTheFunctionDomain
k+2+13*3(-9)

We add all the numbers together, and all the variables

k-349

Back to the equation:

-(k-349)


We get rid of parentheses

-k+349=0

We add all the numbers together, and all the variables

-1k+349=0

We move all terms containing k to the left, all other terms to the right

-k=-349

k=-349/-1

k=+349