13=2(u+2)-5u

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Solution for 13=2(u+2)-5u equation: 



13=2(u+2)-5u

We move all terms to the left:

13-(2(u+2)-5u)=0



We calculate terms in parentheses: -(2(u+2)-5u), so:

2(u+2)-5u

We add all the numbers together, and all the variables

-5u+2(u+2)

We multiply parentheses

-5u+2u+4

We add all the numbers together, and all the variables

-3u+4

Back to the equation:

-(-3u+4)



We get rid of parentheses

3u-4+13=0

We add all the numbers together, and all the variables

3u+9=0

We move all terms containing u to the left, all other terms to the right

3u=-9

u=-9/3

u=-3

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