13=2(5c-2)=29

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Solution for 13=2(5c-2)=29 equation: 



13=2(5c-2)=29

We move all terms to the left:

13-(2(5c-2))=0



We calculate terms in parentheses: -(2(5c-2)), so:

2(5c-2)

We multiply parentheses

10c-4

Back to the equation:

-(10c-4)



We get rid of parentheses

-10c+4+13=0

We add all the numbers together, and all the variables

-10c+17=0

We move all terms containing c to the left, all other terms to the right

-10c=-17

c=-17/-10

c=1+7/10

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