13=-2(k-4)+3k

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Solution for 13=-2(k-4)+3k equation: 



13=-2(k-4)+3k

We move all terms to the left:

13-(-2(k-4)+3k)=0



We calculate terms in parentheses: -(-2(k-4)+3k), so:

-2(k-4)+3k

We add all the numbers together, and all the variables

3k-2(k-4)

We multiply parentheses

3k-2k+8

We add all the numbers together, and all the variables

k+8

Back to the equation:

-(k+8)



We get rid of parentheses

-k-8+13=0

We add all the numbers together, and all the variables

-1k+5=0

We move all terms containing k to the left, all other terms to the right

-k=-5

k=-5/-1

k=+5

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