138-2(6x-3)=15(2x-3)=20(5x-7)-75

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Solution for 138-2(6x-3)=15(2x-3)=20(5x-7)-75 equation: 



138-2(6x-3)=15(2x-3)=20(5x-7)-75

We move all terms to the left:

138-2(6x-3)-(15(2x-3))=0

We multiply parentheses

-12x-(15(2x-3))+6+138=0



We calculate terms in parentheses: -(15(2x-3)), so:

15(2x-3)

We multiply parentheses

30x-45

Back to the equation:

-(30x-45)



We add all the numbers together, and all the variables

-12x-(30x-45)+144=0

We get rid of parentheses

-12x-30x+45+144=0

We add all the numbers together, and all the variables

-42x+189=0

We move all terms containing x to the left, all other terms to the right

-42x=-189

x=-189/-42

x=4+1/2

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