136j(1+1=0)

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Solution for 136j(1+1=0) equation: 



136j(1+1=0)

We move all terms to the left:

136j(1+1-(0))=0

We add all the numbers together, and all the variables

136j2=0

We add all the numbers together, and all the variables

136j^2=0

a = 136; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·136·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$j=\frac{-b}{2a}=\frac{0}{272}=0$

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