136-(7x+11)=7(x+5)+x

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Solution for 136-(7x+11)=7(x+5)+x equation: 



136-(7x+11)=7(x+5)+x

We move all terms to the left:

136-(7x+11)-(7(x+5)+x)=0

We get rid of parentheses

-7x-(7(x+5)+x)-11+136=0



We calculate terms in parentheses: -(7(x+5)+x), so:

7(x+5)+x

We add all the numbers together, and all the variables

x+7(x+5)

We multiply parentheses

x+7x+35

We add all the numbers together, and all the variables

8x+35

Back to the equation:

-(8x+35)



We add all the numbers together, and all the variables

-7x-(8x+35)+125=0

We get rid of parentheses

-7x-8x-35+125=0

We add all the numbers together, and all the variables

-15x+90=0

We move all terms containing x to the left, all other terms to the right

-15x=-90

x=-90/-15

x=+6

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