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1350=(x+15)(x)
We move all terms to the left:
1350-((x+15)(x))=0
We calculate terms in parentheses: -((x+15)x), so:We get rid of parentheses
(x+15)x
We multiply parentheses
x^2+15x
Back to the equation:
-(x^2+15x)
-x^2-15x+1350=0
We add all the numbers together, and all the variables
-1x^2-15x+1350=0
a = -1; b = -15; c = +1350;
Δ = b2-4ac
Δ = -152-4·(-1)·1350
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-75}{2*-1}=\frac{-60}{-2} =+30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+75}{2*-1}=\frac{90}{-2} =-45 $
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