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1350=(x)(x-1)(10)
We move all terms to the left:
1350-((x)(x-1)(10))=0
We calculate terms in parentheses: -(x(x-1)10), so:We get rid of parentheses
x(x-1)10
We multiply parentheses
10x^2-10x
Back to the equation:
-(10x^2-10x)
-10x^2+10x+1350=0
a = -10; b = 10; c = +1350;
Δ = b2-4ac
Δ = 102-4·(-10)·1350
Δ = 54100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{54100}=\sqrt{100*541}=\sqrt{100}*\sqrt{541}=10\sqrt{541}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{541}}{2*-10}=\frac{-10-10\sqrt{541}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{541}}{2*-10}=\frac{-10+10\sqrt{541}}{-20} $
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