133=7n+5(1+5n)

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Solution for 133=7n+5(1+5n) equation: 



133=7n+5(1+5n)

We move all terms to the left:

133-(7n+5(1+5n))=0

We add all the numbers together, and all the variables

-(7n+5(5n+1))+133=0



We calculate terms in parentheses: -(7n+5(5n+1)), so:

7n+5(5n+1)

We multiply parentheses

7n+25n+5

We add all the numbers together, and all the variables

32n+5

Back to the equation:

-(32n+5)



We get rid of parentheses

-32n-5+133=0

We add all the numbers together, and all the variables

-32n+128=0

We move all terms containing n to the left, all other terms to the right

-32n=-128

n=-128/-32

n=+4

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