133=7(4v+3)

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Solution for 133=7(4v+3) equation: 



133=7(4v+3)

We move all terms to the left:

133-(7(4v+3))=0



We calculate terms in parentheses: -(7(4v+3)), so:

7(4v+3)

We multiply parentheses

28v+21

Back to the equation:

-(28v+21)



We get rid of parentheses

-28v-21+133=0

We add all the numbers together, and all the variables

-28v+112=0

We move all terms containing v to the left, all other terms to the right

-28v=-112

v=-112/-28

v=+4

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