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133=(2x-5)+x
We move all terms to the left:
133-((2x-5)+x)=0
We calculate terms in parentheses: -((2x-5)+x), so:We get rid of parentheses
(2x-5)+x
We add all the numbers together, and all the variables
x+(2x-5)
We get rid of parentheses
x+2x-5
We add all the numbers together, and all the variables
3x-5
Back to the equation:
-(3x-5)
-3x+5+133=0
We add all the numbers together, and all the variables
-3x+138=0
We move all terms containing x to the left, all other terms to the right
-3x=-138
x=-138/-3
x=+46
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