132=3+(n-1)+3

Solution for 132=3+(n-1)+3 equation:

132=3+(n-1)+3

We move all terms to the left:

132-(3+(n-1)+3)=0


We calculate terms in parentheses: -(3+(n-1)+3), so:

3+(n-1)+3

determiningTheFunctionDomain
(n-1)+3+3

We add all the numbers together, and all the variables

(n-1)+6

We get rid of parentheses

n-1+6

We add all the numbers together, and all the variables

n+5

Back to the equation:

-(n+5)


We get rid of parentheses

-n-5+132=0

We add all the numbers together, and all the variables

-1n+127=0

We move all terms containing n to the left, all other terms to the right

-n=-127

n=-127/-1

n=+127