132=(n-1)

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Solution for 132=(n-1) equation: 



132=(n-1)

We move all terms to the left:

132-((n-1))=0



We calculate terms in parentheses: -((n-1)), so:

(n-1)

We get rid of parentheses

n-1

Back to the equation:

-(n-1)



We get rid of parentheses

-n+1+132=0

We add all the numbers together, and all the variables

-1n+133=0

We move all terms containing n to the left, all other terms to the right

-n=-133

n=-133/-1

n=+133

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