132=(2w+10)w

Solution for 132=(2w+10)w equation:

132=(2w+10)w

We move all terms to the left:

132-((2w+10)w)=0


We calculate terms in parentheses: -((2w+10)w), so:

(2w+10)w

We multiply parentheses

2w^2+10w

Back to the equation:

-(2w^2+10w)


We get rid of parentheses

-2w^2-10w+132=0

a = -2; b = -10; c = +132;
Δ = b2-4ac
Δ = -102-4·(-2)·132
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-34}{2*-2}=\frac{-24}{-4}
=+6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+34}{2*-2}=\frac{44}{-4}
=-11
$