130v2=169

Solution for 130v2=169 equation:

130v^2=169

We move all terms to the left:

130v^2-(169)=0

a = 130; b = 0; c = -169;
Δ = b2-4ac
Δ = 02-4·130·(-169)
Δ = 87880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{87880}=\sqrt{676*130}=\sqrt{676}*\sqrt{130}=26\sqrt{130}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26\sqrt{130}}{2*130}=\frac{0-26\sqrt{130}}{260}
=-\frac{26\sqrt{130}}{260}
=-\frac{\sqrt{130}}{10}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26\sqrt{130}}{2*130}=\frac{0+26\sqrt{130}}{260}
=\frac{26\sqrt{130}}{260}
=\frac{\sqrt{130}}{10}
$