130=x2+2x+35

Solution for 130=x2+2x+35 equation:

130=x2+2x+35

We move all terms to the left:

130-(x2+2x+35)=0

We add all the numbers together, and all the variables

-(+x^2+2x+35)+130=0

We get rid of parentheses

-x^2-2x-35+130=0

We add all the numbers together, and all the variables

-1x^2-2x+95=0

a = -1; b = -2; c = +95;
Δ = b2-4ac
Δ = -22-4·(-1)·95
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-8\sqrt{6}}{2*-1}=\frac{2-8\sqrt{6}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+8\sqrt{6}}{2*-1}=\frac{2+8\sqrt{6}}{-2}
$