130=7(2+4n)+n

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Solution for 130=7(2+4n)+n equation: 



130=7(2+4n)+n

We move all terms to the left:

130-(7(2+4n)+n)=0

We add all the numbers together, and all the variables

-(7(4n+2)+n)+130=0



We calculate terms in parentheses: -(7(4n+2)+n), so:

7(4n+2)+n

We add all the numbers together, and all the variables

n+7(4n+2)

We multiply parentheses

n+28n+14

We add all the numbers together, and all the variables

29n+14

Back to the equation:

-(29n+14)



We get rid of parentheses

-29n-14+130=0

We add all the numbers together, and all the variables

-29n+116=0

We move all terms containing n to the left, all other terms to the right

-29n=-116

n=-116/-29

n=+4

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