130=3(-7k+5)-2k

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Solution for 130=3(-7k+5)-2k equation: 



130=3(-7k+5)-2k

We move all terms to the left:

130-(3(-7k+5)-2k)=0



We calculate terms in parentheses: -(3(-7k+5)-2k), so:

3(-7k+5)-2k

We add all the numbers together, and all the variables

-2k+3(-7k+5)

We multiply parentheses

-2k-21k+15

We add all the numbers together, and all the variables

-23k+15

Back to the equation:

-(-23k+15)



We get rid of parentheses

23k-15+130=0

We add all the numbers together, and all the variables

23k+115=0

We move all terms containing k to the left, all other terms to the right

23k=-115

k=-115/23

k=-5

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