130=1+3(1-7b)

Solution for 130=1+3(1-7b) equation:

130=1+3(1-7b)

We move all terms to the left:

130-(1+3(1-7b))=0

We add all the numbers together, and all the variables

-(1+3(-7b+1))+130=0


We calculate terms in parentheses: -(1+3(-7b+1)), so:

1+3(-7b+1)

determiningTheFunctionDomain
3(-7b+1)+1

We multiply parentheses

-21b+3+1

We add all the numbers together, and all the variables

-21b+4

Back to the equation:

-(-21b+4)


We get rid of parentheses

21b-4+130=0

We add all the numbers together, and all the variables

21b+126=0

We move all terms containing b to the left, all other terms to the right

21b=-126

b=-126/21

b=-6