130+108=(13+2x)(10+2x)

Solution for 130+108=(13+2x)(10+2x) equation:

130+108=(13+2x)(10+2x)

We move all terms to the left:

130+108-((13+2x)(10+2x))=0

We add all the numbers together, and all the variables

-((2x+13)(2x+10))+130+108=0

We add all the numbers together, and all the variables

-((2x+13)(2x+10))+238=0

We multiply parentheses ..

-((+4x^2+20x+26x+130))+238=0


We calculate terms in parentheses: -((+4x^2+20x+26x+130)), so:

(+4x^2+20x+26x+130)

We get rid of parentheses

4x^2+20x+26x+130

We add all the numbers together, and all the variables

4x^2+46x+130

Back to the equation:

-(4x^2+46x+130)


We get rid of parentheses

-4x^2-46x-130+238=0

We add all the numbers together, and all the variables

-4x^2-46x+108=0

a = -4; b = -46; c = +108;
Δ = b2-4ac
Δ = -462-4·(-4)·108
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-62}{2*-4}=\frac{-16}{-8}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+62}{2*-4}=\frac{108}{-8}
=-13+1/2
$