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13/a+5=5/2a+13
We move all terms to the left:
13/a+5-(5/2a+13)=0
Domain of the equation: a!=0
a∈R
Domain of the equation: 2a+13)!=0We get rid of parentheses
a∈R
13/a-5/2a-13+5=0
We calculate fractions
26a/2a^2+(-5a)/2a^2-13+5=0
We add all the numbers together, and all the variables
26a/2a^2+(-5a)/2a^2-8=0
We multiply all the terms by the denominator
26a+(-5a)-8*2a^2=0
Wy multiply elements
-16a^2+26a+(-5a)=0
We get rid of parentheses
-16a^2+26a-5a=0
We add all the numbers together, and all the variables
-16a^2+21a=0
a = -16; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·(-16)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*-16}=\frac{-42}{-32} =1+5/16 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*-16}=\frac{0}{-32} =0 $
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