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13/6x-x=5
We move all terms to the left:
13/6x-x-(5)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
-1x+13/6x-5=0
We multiply all the terms by the denominator
-1x*6x-5*6x+13=0
Wy multiply elements
-6x^2-30x+13=0
a = -6; b = -30; c = +13;
Δ = b2-4ac
Δ = -302-4·(-6)·13
Δ = 1212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1212}=\sqrt{4*303}=\sqrt{4}*\sqrt{303}=2\sqrt{303}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{303}}{2*-6}=\frac{30-2\sqrt{303}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{303}}{2*-6}=\frac{30+2\sqrt{303}}{-12} $
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