13-5b-3b=2(-2b-3)+11

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Solution for 13-5b-3b=2(-2b-3)+11 equation: 



13-5b-3b=2(-2b-3)+11

We move all terms to the left:

13-5b-3b-(2(-2b-3)+11)=0

We add all the numbers together, and all the variables

-8b-(2(-2b-3)+11)+13=0



We calculate terms in parentheses: -(2(-2b-3)+11), so:

2(-2b-3)+11

We multiply parentheses

-4b-6+11

We add all the numbers together, and all the variables

-4b+5

Back to the equation:

-(-4b+5)



We get rid of parentheses

-8b+4b-5+13=0

We add all the numbers together, and all the variables

-4b+8=0

We move all terms containing b to the left, all other terms to the right

-4b=-8

b=-8/-4

b=+2

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