13-2(x+1)=12-3(3+2x)

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Solution for 13-2(x+1)=12-3(3+2x) equation: 



13-2(x+1)=12-3(3+2x)

We move all terms to the left:

13-2(x+1)-(12-3(3+2x))=0

We add all the numbers together, and all the variables

-2(x+1)-(12-3(2x+3))+13=0

We multiply parentheses

-2x-(12-3(2x+3))-2+13=0



We calculate terms in parentheses: -(12-3(2x+3)), so:

12-3(2x+3)

determiningTheFunctionDomain
-3(2x+3)+12

We multiply parentheses

-6x-9+12

We add all the numbers together, and all the variables

-6x+3

Back to the equation:

-(-6x+3)



We add all the numbers together, and all the variables

-2x-(-6x+3)+11=0

We get rid of parentheses

-2x+6x-3+11=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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