13-(3k-5)=4(3k+2)

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Solution for 13-(3k-5)=4(3k+2) equation: 



13-(3k-5)=4(3k+2)

We move all terms to the left:

13-(3k-5)-(4(3k+2))=0

We get rid of parentheses

-3k-(4(3k+2))+5+13=0



We calculate terms in parentheses: -(4(3k+2)), so:

4(3k+2)

We multiply parentheses

12k+8

Back to the equation:

-(12k+8)



We add all the numbers together, and all the variables

-3k-(12k+8)+18=0

We get rid of parentheses

-3k-12k-8+18=0

We add all the numbers together, and all the variables

-15k+10=0

We move all terms containing k to the left, all other terms to the right

-15k=-10

k=-10/-15

k=2/3

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