13-(3-k)=5(k+2)

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Solution for 13-(3-k)=5(k+2) equation: 



13-(3-k)=5(k+2)

We move all terms to the left:

13-(3-k)-(5(k+2))=0

We add all the numbers together, and all the variables

-(-1k+3)-(5(k+2))+13=0

We get rid of parentheses

1k-(5(k+2))-3+13=0



We calculate terms in parentheses: -(5(k+2)), so:

5(k+2)

We multiply parentheses

5k+10

Back to the equation:

-(5k+10)



We add all the numbers together, and all the variables

k-(5k+10)+10=0

We get rid of parentheses

k-5k-10+10=0

We add all the numbers together, and all the variables

-4k=0

k=0/-4

k=0

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