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13-(2n+2)=2(n+2)+3
We move all terms to the left:
13-(2n+2)-(2(n+2)+3)=0
We get rid of parentheses
-2n-(2(n+2)+3)-2+13=0
We calculate terms in parentheses: -(2(n+2)+3), so:We add all the numbers together, and all the variables
2(n+2)+3
We multiply parentheses
2n+4+3
We add all the numbers together, and all the variables
2n+7
Back to the equation:
-(2n+7)
-2n-(2n+7)+11=0
We get rid of parentheses
-2n-2n-7+11=0
We add all the numbers together, and all the variables
-4n+4=0
We move all terms containing n to the left, all other terms to the right
-4n=-4
n=-4/-4
n=1
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