13-(2c=2)=2(c+2)+3c

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Solution for 13-(2c=2)=2(c+2)+3c equation: 



13-(2c=2)=2(c+2)+3c

We move all terms to the left:

13-(2c-(2))=0

We get rid of parentheses

-2c+2+13=0

We add all the numbers together, and all the variables

-2c+15=0

We move all terms containing c to the left, all other terms to the right

-2c=-15

c=-15/-2

c=7+1/2

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