13-(2c-2)=2(c+2)=3c

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Solution for 13-(2c-2)=2(c+2)=3c equation: 



13-(2c-2)=2(c+2)=3c

We move all terms to the left:

13-(2c-2)-(2(c+2))=0

We get rid of parentheses

-2c-(2(c+2))+2+13=0



We calculate terms in parentheses: -(2(c+2)), so:

2(c+2)

We multiply parentheses

2c+4

Back to the equation:

-(2c+4)



We add all the numbers together, and all the variables

-2c-(2c+4)+15=0

We get rid of parentheses

-2c-2c-4+15=0

We add all the numbers together, and all the variables

-4c+11=0

We move all terms containing c to the left, all other terms to the right

-4c=-11

c=-11/-4

c=2+3/4

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