13-(2c+2)=2(c+2)3

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Solution for 13-(2c+2)=2(c+2)3 equation:


Simplifying
13 + -1(2c + 2) = 2(c + 2) * 3

Reorder the terms:
13 + -1(2 + 2c) = 2(c + 2) * 3
13 + (2 * -1 + 2c * -1) = 2(c + 2) * 3
13 + (-2 + -2c) = 2(c + 2) * 3

Combine like terms: 13 + -2 = 11
11 + -2c = 2(c + 2) * 3

Reorder the terms:
11 + -2c = 2(2 + c) * 3

Reorder the terms for easier multiplication:
11 + -2c = 2 * 3(2 + c)

Multiply 2 * 3
11 + -2c = 6(2 + c)
11 + -2c = (2 * 6 + c * 6)
11 + -2c = (12 + 6c)

Solving
11 + -2c = 12 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
11 + -2c + -6c = 12 + 6c + -6c

Combine like terms: -2c + -6c = -8c
11 + -8c = 12 + 6c + -6c

Combine like terms: 6c + -6c = 0
11 + -8c = 12 + 0
11 + -8c = 12

Add '-11' to each side of the equation.
11 + -11 + -8c = 12 + -11

Combine like terms: 11 + -11 = 0
0 + -8c = 12 + -11
-8c = 12 + -11

Combine like terms: 12 + -11 = 1
-8c = 1

Divide each side by '-8'.
c = -0.125

Simplifying
c = -0.125

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