13+2x=3x+4(x+3)

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Solution for 13+2x=3x+4(x+3) equation: 



13+2x=3x+4(x+3)

We move all terms to the left:

13+2x-(3x+4(x+3))=0



We calculate terms in parentheses: -(3x+4(x+3)), so:

3x+4(x+3)

We multiply parentheses

3x+4x+12

We add all the numbers together, and all the variables

7x+12

Back to the equation:

-(7x+12)



We get rid of parentheses

2x-7x-12+13=0

We add all the numbers together, and all the variables

-5x+1=0

We move all terms containing x to the left, all other terms to the right

-5x=-1

x=-1/-5

x=1/5

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