13+(-7)-10t=2

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Solution for 13+(-7)-10t=2 equation: 



13+(-7)-10t=2

We move all terms to the left:

13+(-7)-10t-(2)=0

determiningTheFunctionDomain
-10t+13-2+(-7)=0

We add all the numbers together, and all the variables

-10t+4=0

We move all terms containing t to the left, all other terms to the right

-10t=-4

t=-4/-10

t=2/5

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