13(y-2)=3(4y+4)-38

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Solution for 13(y-2)=3(4y+4)-38 equation:


Simplifying
13(y + -2) = 3(4y + 4) + -38

Reorder the terms:
13(-2 + y) = 3(4y + 4) + -38
(-2 * 13 + y * 13) = 3(4y + 4) + -38
(-26 + 13y) = 3(4y + 4) + -38

Reorder the terms:
-26 + 13y = 3(4 + 4y) + -38
-26 + 13y = (4 * 3 + 4y * 3) + -38
-26 + 13y = (12 + 12y) + -38

Reorder the terms:
-26 + 13y = 12 + -38 + 12y

Combine like terms: 12 + -38 = -26
-26 + 13y = -26 + 12y

Add '26' to each side of the equation.
-26 + 26 + 13y = -26 + 26 + 12y

Combine like terms: -26 + 26 = 0
0 + 13y = -26 + 26 + 12y
13y = -26 + 26 + 12y

Combine like terms: -26 + 26 = 0
13y = 0 + 12y
13y = 12y

Solving
13y = 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.
13y + -12y = 12y + -12y

Combine like terms: 13y + -12y = 1y
1y = 12y + -12y

Combine like terms: 12y + -12y = 0
1y = 0

Divide each side by '1'.
y = 0

Simplifying
y = 0

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