13(n+1)=1/6(3n-5)

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Solution for 13(n+1)=1/6(3n-5) equation: 



13(n+1)=1/6(3n-5)

We move all terms to the left:

13(n+1)-(1/6(3n-5))=0



Domain of the equation: 6(3n-5))!=0

n∈R



We multiply parentheses

13n-(1/6(3n-5))+13=0

We multiply all the terms by the denominator


13n*6(3n-5))-(1+13*6(3n-5))=0

Wy multiply elements

78n^2(3+78n(3=0

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