13(d-9)=4(d-9)+9d-81

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Solution for 13(d-9)=4(d-9)+9d-81 equation: 



13(d-9)=4(d-9)+9d-81

We move all terms to the left:

13(d-9)-(4(d-9)+9d-81)=0

We multiply parentheses

13d-(4(d-9)+9d-81)-117=0



We calculate terms in parentheses: -(4(d-9)+9d-81), so:

4(d-9)+9d-81

We add all the numbers together, and all the variables

9d+4(d-9)-81

We multiply parentheses

9d+4d-36-81

We add all the numbers together, and all the variables

13d-117

Back to the equation:

-(13d-117)



We get rid of parentheses

13d-13d+117-117=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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